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发表于 2015-12-25 10:33:48
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回复 2# 若枫 ! X. S/ a- _% V
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老大:
0 I3 B. b- n6 a& T 感谢您的回复!以下是我的方法,这样的确出来两个G代码。
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if drillcyc$ = 9,/ A+ v/ R- \2 T( H. t' {
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pdrlcommonb; K3 z% V' j% b: C" D
peck1st =peck1$* \7 w' f K- Z6 d9 A9 _' N
if dwell$ = 0,pcan1, pbld, n$, *sgdrlref, "G1181", pxout, pyout, pfzout,* A9 H8 G# p$ g9 [( b1 f/ w. F
prdrlout, dwell$, *peck1st, *peck2$, *feed, strcantext, e$
( e* D& x4 j3 @( L& ~0 z else, pcan1, pbld, n$, *sgdrlref, "G1182", pxout, pyout, pfzout,% { \& B Q5 e- x% T
prdrlout, dwell$, *peck1st, *peck2$, *feed, strcantext, e$
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但使用以下的方法出不来一个钻孔循环两个不同的G代码。上面的"G1181”用原来的*sgdrill出来的是G81
N$ A3 j9 a: xsg85 : "G85" #bore #1 - no dwell
+ N% Y0 B% d* V7 q& U+ j, K0 i" ]" Asg85d : "G89" #bore #1 - with dwell
( v: \7 D( u# f) Q4 y' Msg86 : "G86" #bore #2 - no dwell& ^! ]1 V8 X: u% Y
sg86d : "G86" #bore #2 - with dwell9 P0 E2 y$ l" A; ]1 b
sgm1 : "G76" #fine bore - no dwell
( c+ ~* A" S; W, r( ]: }1 osgm1d : "G87" #fine bore - with dwell
; {6 _( A; ^- @& y# I: G, o) Wsgm2 : "G84" #rigid tap - right hand" x% t/ R# a. f8 ?/ }+ [1 K
sgm2d : "G74" #rigid tap - left hand# q) j" _5 s ?- F* U4 Y
sgc9 : "G183" #custom #9 - no dwell
$ ~3 e% b! d( T" _: {sgc9d : "G184" #custom #9 - with dwell. k1 v( |2 h) v* i8 ]% G( L: O* Y% |
sgc10 : "G185" #custom #10 - no dwell
; x' {$ v3 ^9 Z: m4 p/ e% B; wsgc10d : "G186" #custom #10 - with dwell) _: G, q' \8 _( `/ V' n8 w/ x
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! ?$ W! ?- I* l5 U2 m7 m" \请指点一二,谢谢!& j# a' a8 f: x
最终我要出25个左右钻孔循环,30多个G代码。 |
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