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发表于 2015-12-25 10:33:48
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回复 2# 若枫 6 i$ P2 g0 t! i+ w$ R0 H" k; ~6 I0 k
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老大:* a$ s. T2 D' s- D# F) l
感谢您的回复!以下是我的方法,这样的确出来两个G代码。7 Y: j6 C* v! m( Z/ }6 k
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2 m n5 ]7 E6 Z) u& Q6 y if drillcyc$ = 9,
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9 n6 G; H% U- E5 f9 i( P$ I pdrlcommonb
3 N1 u X4 b3 ]3 k' `! c4 o. ` peck1st =peck1$6 G. U+ N( a0 _% X
if dwell$ = 0,pcan1, pbld, n$, *sgdrlref, "G1181", pxout, pyout, pfzout,
) M# X; K# W! l! q5 o prdrlout, dwell$, *peck1st, *peck2$, *feed, strcantext, e$! a9 g8 d' y' M; m( k4 k) h
else, pcan1, pbld, n$, *sgdrlref, "G1182", pxout, pyout, pfzout,
3 ^; H1 p- t* G. L1 x: s* L prdrlout, dwell$, *peck1st, *peck2$, *feed, strcantext, e$
9 Y/ J0 T9 C1 a( S9 u$ M pcom_movea8 Y( o' S0 O3 c; d, S
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但使用以下的方法出不来一个钻孔循环两个不同的G代码。上面的"G1181”用原来的*sgdrill出来的是G81
! g/ C% |9 \3 {/ ]sg85 : "G85" #bore #1 - no dwell
0 z4 O$ J& P* X% ksg85d : "G89" #bore #1 - with dwell
d/ @" u( b( [3 t: Qsg86 : "G86" #bore #2 - no dwell
' O, e: e( q6 h# |sg86d : "G86" #bore #2 - with dwell
0 Y4 q: P; Q# i: bsgm1 : "G76" #fine bore - no dwell6 {; R8 h1 ]$ ?" b. X
sgm1d : "G87" #fine bore - with dwell
. }8 D ?& M) W/ T8 {7 lsgm2 : "G84" #rigid tap - right hand
4 `0 d2 w* s" j gsgm2d : "G74" #rigid tap - left hand0 d# Y3 J* A0 R( c" ]
sgc9 : "G183" #custom #9 - no dwell
' D2 [6 B0 o1 O" u* b5 @) Isgc9d : "G184" #custom #9 - with dwell Q8 ~1 v& d% I4 w
sgc10 : "G185" #custom #10 - no dwell
0 J+ ?4 \) r# Z! g7 _: Hsgc10d : "G186" #custom #10 - with dwell# L" p4 e/ B1 L
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+ n$ t. i. S: q" s" L请指点一二,谢谢!
! y2 n7 M* O: k* d; ~最终我要出25个左右钻孔循环,30多个G代码。 |
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